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What does console.log({ a: 1 } === { a: 1 }) print? JavaScript Objects, Destructuring and Immutability
Block 5, Objects, Destructuring and Immutability, question 6 of the JavaScript sample
console.log({ a: 1 } === { a: 1 });What does this print?
Show the answer and why each option is right or wrong
Answer, C. false
- A. undefined
- Assumes the comparison silently fails to produce a boolean when neither side is a named variable.
- B. TypeError
- Assumes comparing two freshly created object literals directly is not valid syntax.
- C. false
- Correct. Strict equality on two objects compares references, and these are two distinct object literals, so the comparison is false.
- D. true
- Assumes two object literals with identical contents are considered equal by strict equality.
Strict equality between two objects never inspects their properties, it only checks whether both sides refer to the exact same object in memory. Two separate object literals, even with identical shape and values, are always two different objects.
The answer above is what the Node interpreter printed when the snippet was run, not what someone expected it to do.
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