What does print(all([1, 2, 0])) print? Python Lists, Tuples and Slicing

Answer, B. False

A. None

Assumes encountering a falsy element makes all() report that there is no valid answer instead of a definite False.

B. False

Correct. all() requires every element to be truthy, and the 0 in this list is falsy, so the overall result is False even though the other two elements are truthy.

C. True

Checks only that the list itself is non empty instead of checking the truthiness of each individual element.

D. 0

Assumes all() returns the first falsy element it finds instead of a plain boolean.

all() short circuits as soon as it finds a single falsy element and returns False at that point, regardless of how many truthy elements came before or after it. A single 0 anywhere in the iterable is enough to make the whole result False.